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e^(x) - 3e^(-x) - 2 = 0 Having a little trouble solving for x.
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e^(x) - 3e^(-x)=2 Ln(e^(x) - 3e^(-x))=Ln2 Ln(e^(x))-3Ln(e^(-x))=Ln2 Ln(e^x/3e^(-x))=Ln2 Ln(e^2x/3)=Ln2 2xLn(1/3)=Ln2 continue
I'm getting x = ln(2) / 2ln(1/3) , which is wrong according to my book
thanks
e^(x) - 3e^(-x)=2 Ln(e^(x) - 3e^(-x))=Ln2 Ln(e^(x))-Ln(e^(-3x))=Ln2 Ln(e^x/e^(-3x))=Ln2 Ln(e^4x)=Ln2 4x=Ln2
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