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Complete the square to solve the equation below. x^2+x=19/4
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hey buddy can you help please
\[adding both sides \left( \frac{ co-efficient of x }{2 } \right)^{2}=\left( \frac{ 1 }{2} \right)^{2} =\frac{ 1 }{4 }\]
1/4 isnt the answer
i have given you the hint.
can you proceed further
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\[x=-\frac{ 1 }{ 2}+\sqrt{5}\]
right
\[x=-\frac{ 1 }{ 2 }\pm \sqrt{5}\]
oh okay i was right except for the +/-
yes
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thanks
yw
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