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How many units apart are the points (4, -3) and (-4, 3)?
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\(\bf \text{distance between 2 points}\\ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)
I got 5.29 is that correct? @jdoe0001
@jdoe0001
\(\bf d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\\ \textit{(4, -3), (-4, 3)}\\ d = \sqrt{((-4)-(4))^2 + ((3)-(-3))^2} \implies \sqrt{(-8)^2+(6)^2}\)
(-8)2= -64 (6)2=36
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\(\bf (-8)^2 \implies -8 \times -8\)
64
square root of 96 is 9.79
\(\bf d = \sqrt{((-4)-(4))^2 + ((3)-(-3))^2} \implies \sqrt{(-8)^2+(6)^2}\\ \implies \sqrt{64+36}\)
64+36=96
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I mean 100
oh its 10
:)
I got it thanks
yw
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