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OpenStudy (erinweeks):
Complete the identity
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OpenStudy (erinweeks):
\[\frac{ \cos(\alpha-\beta) }{\cos \alpha \cos \beta }\]
OpenStudy (anonymous):
\[\frac{ \cos(a)\cos(b) + \sin(a)\sin(b) }{ \cos(a)\cos(b) }\]
\[\tan(a)\tan(b)\]
Is this it? or can someone else simplify it further?...
OpenStudy (erinweeks):
well @greenleaf800073 these are the answers
A. 1 + cot α cot β
B. tan α tan β + cot β
C. 1 + tan α tan β
D. 1 + cot α tan β
OpenStudy (erinweeks):
@jim_thompson5910 @Hero ??
OpenStudy (anonymous):
AH, WOOPS
It's C
hehe, forgot to add the 1 +
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OpenStudy (erinweeks):
okay thanks @greenleaf800073 i got one more of these could you help?
OpenStudy (anonymous):
sure
OpenStudy (erinweeks):
\[\frac{ \sin(\alpha +\beta) }{ \cos \alpha \cos \beta }\]
OpenStudy (erinweeks):
A. cot α + cot β
B. tan α + tan β
C. tan β + tan α
D. -tan α + cot β
OpenStudy (erinweeks):
@greenleaf800073 ???
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OpenStudy (anonymous):
\[\frac{ \sin(a)\cos(b) + \cos(a)\sin(b) }{ \cos(a)\cos(b) }\]
\[tan(a) + tan(b)\]
I'm only 90% sure on this answer, anyone want to reassure?
OpenStudy (erinweeks):
i'll just try it and let ya know (:
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