Solve 7^(x - 2) = 12^x
Gotta use log...
i know that much, but the thing is I got the answer, x = 3.28, and not the right answer of -7.22, if you could just give me the step by step process that would be great
Okay:)
ok so here's what I did, just instruct me on what i did wrong
7^(x-2)=12^(x) ln(7^(x-2))=ln(12^(x)) xln(7)-2ln(7)=ln(12^(x)) xln(7)-2ln(7)-xln(12)=0 x(ln(7)-ln(12))=2ln(7) x=(2ln(7))/(ln(7)-ln(12)) x=3.8918
\[(x-2)(\log(7)) =(x) \log(12) \]
\[(x-2) (.8450984) = x(1.079181246)\]
Uh hu...The sooner you turn it into a decimal the faster it gets farther from an exact answer. Just sayin. I think you did it correctly just rounding got the best of you!
I"m not really rounding, I'm just putting out what the calc it putting out
it's worked for all the other ones
Well the calculator is rounding lol.
yeah i guess the calc rounds
lol
Thanks though! I get it now
Good:)
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