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Please help fast!! I will give medal. Find the area of the triangle having the indicated sides and angle with B=72 degrees 30', a=105 and c=64?
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Can you draw the triangle and mark the given values on it?
There is a formula for finding the area of triangle with 2 adjacent sides and one angle between them.
\[Area=\frac{ 1 }{ 2 }(a \times c)\sin B\]
Where a and b are adjacent sides and B is the angle between them.
Substituting the values, you get : Area = 0.5 * ( 105 * 64 ) * 0.95 = 3192 unit sq.
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