What is the solution set for |–4x – 8| = 4? x = 3 and x = 1 x = 3 and x = –1 x = –3 and x = 1 x = –3 and x = –1
I think its C
Ok let us see..
yaw two or three opinions are needed
|a| = b a = b or a = -b
explain it not give the answer yet
It's a method, not the answer...
\[ |–4x – 8| = 4 \rightarrow –4x – 8 = \pm4 \rightarrow –4x = \pm4 +8\] –4x = 4 +8 or –4x = -4 +8 -4x= 12 or -4x=4 x=12/(-4) or x= 4/(-4) x=3 or x=-1 Thus second option appears to be true
yup i thin so too
Okay well im not sure if this is the right way to do it but -4x-8=4 +8 +8 -4x=12 divide by 4 divide by 4 x=3 0r 1
yess i feel stupid -_- lol
Hmm these are the answers im coming up with :[ \[\large -4x-8=4 \qquad\to\qquad x=-3\]\[\large -4x-8=-4 \qquad\to\qquad x=-1\]
In your last step there, diving by 4 gives you\[-4x=12 \qquad\to\qquad -x=3\]
dividing*
So how do i solve these correctly how @dpasingh did it ?
He did it incorrectly I'm afraid. :[\[\Large -4x-8=4\]Adding 8 to each side,\[\Large -4x=12\]dividing each side by -4,\[\Large x=-3\] The other solution,\[\Large -4x-8=-4\]Adding 8 to each side,\[\Large -4x=4\]Dividing each side by -4,\[\Large x=-1\]
so i was kinda right ? lol
With your C guess? :) lol Yah I guess so, you had one of the solutions correct at least ^^ hehe
Err your last guess, where you showed the work ~ looks good, just don't forget about those negatives when you divide :)
Okay lol thank you so much :)
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