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the sum of 5 consecutive even integers is 70. Find the integers.
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let x be the smallest of the 5 integers
that would mean x+2 is the next consecutive even integer x+4 is the next consecutive even integer after that etc etc
so we have these 5 consecutive even integers x x+2 x+4 x+6 x+8 add them up and set them equal to 70 x+(x+2)+(x+4)+(x+6)+(x+8) = 70 then solve for x and use this to find the 5 consecutive even integers
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