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h=(-5t-2)(t-2) In this case are we suposed ot factor out the negative 1 from (-5t-2) making it -(5t+2)?
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You could or you can leave it like that Its probably best to factor out that -1 though
But in the second term (t-2) we cannot do anything right?
that is correct, nothing can be done to t-2
also by factoring the negative 1 wont the x-intercept change?
no the x-intercept should remain the same
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Yea it does thanks
yw
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