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\[\frac{ 3x }{ \sqrt{x^3} }\]
what do you want me to do? solve, simplyfie, etc..
I edited the question above :)
nvrmnd lol i just read it. i will try to do it in a sec
alrighty
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\[\frac{3x \sqrt{x ^{3}}}{ x ^{3} }\]
you just have to multiply as follows: 3x \(\sqrt{x^3}\) ----- . ------- \(\sqrt{x^3}\) \(\sqrt{x^3}\)
so it becomes \[\frac{ 3x ^{2}\sqrt{x} }{ x}\]
x^3
its over x^3
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But where did you get that extra x^3 in the numerator?
wat u mean u mulitply both sides by square root x^3
ah ok I see what you mean now
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