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1. 92x = 27x - 1
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so whats the question?
are you solving for x?
its 9^2x=27^x-1
Solving Exponential Equations with Equal Bases."
this is easy
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3^2 is 9 and 3^3 is 27 so basically \[3^{2\times2x}=3^{3(x-1)} \]
so the equations will be \[3^{4x}=3^{3x-3}\]
since the bases are same now u can do 4x=3x-3 and the answer is x=-3
did u get it?
yes thanks
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