Della bought a custom charm bracelet with eight charms. If the bracelet has no clasp, in how many ways can she arrange the charms on the bracelet? please show your work.

Question

Della bought a custom charm bracelet with eight charms.  If the bracelet has no clasp, in how many ways can she arrange the charms on the bracelet? please show your work.

anonymous · Answer

64? 
8 times 8....

zzr0ck3r · Answer

well we can rearange 3 things like this
a,b,c
a,c,b
c,a,b
c,b,a
b,a,c
b,c,a
this is 6
we had three things
so
3! = 3*2 = 6

zzr0ck3r · Answer

similarly we can arrange 4 items 4! =24 ways

anonymous · Answer

Yes ... but the bracelet has no clasp

zzr0ck3r · Answer

what does that have to do with anything?

anonymous · Answer

It means that 

a b c
c a b
b c a

are all the same arrangement

zzr0ck3r · Answer

ahhh

anonymous · Answer

you can just turn the bracelet, because there is no clasp to define any orientation of it

zzr0ck3r · Answer

well looking at my first example of 3 items that would get rid of all but three options

anonymous · Answer

it works out to two

a c b
c b a 
b a c

is the other

anonymous · Answer

So you can start with the factorial, but then you need to divide by the number of charms
to allow for all the positions you can turn the bracelet to

zzr0ck3r · Answer

what class is this for? Discreet?

anonymous · Answer

And it goes further than that ... because you could slip the bracelet on either way, I guess