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If AD=BC, why is AE=BF?
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If AD & BC are trisected.. |dw:1376758896091:dw|
I'm good at math U+I=69.
@SamuelAlden917 a good one huh? XD Silly
Why don’t you be the numerator and I be the denominator and both of us reduce to simplest form?
Bwahaha! You're making me laugh, really.
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1/3>((-1^1/5)/27U)^1/2 Simply this to know how I feel about you. i>3U
*i>3U ? </3 haha
AD=BC \[\frac{ 1 }{3 }AD=\frac{ 1 }{ 3 }BC\] Or AE=BF
Thank you @surjithayer :)
YW
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