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. r(x)=2x+1 s(x)=x^2+2 Find the value of s(r(1)).
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r(x) = 2x + 1 s(x) = x^2 + 2 s(r(x)) = (r(x))^2 + 2 = (2x + 1)^2 + 2
Now substitute x = 1 into s(r(x))
(3(3(1))?
(2(1) + 1)^2 + 2 = 3^2 + 2 = 9 + 2 = 11
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