Look at the figure below.

A triangle ABC is shown. A parallel line DF intersects AB in D and AC in F. Length of AC is 11, AF is 5, AD is x plus 5 and DB is 18

What is the value of x?

Question

Look at the figure below.

A triangle ABC is shown. A parallel line DF intersects AB in D and AC in F. Length of AC is 11, AF is 5, AD is x plus 5 and DB is 18

What is the value of x?

anonymous · Answer

attachment

ganeshie8 · Answer

since FD || CB, the segments of other sides form a proportion.
setup a proportiona nd solve x ?

anonymous · Answer

here are the chocies
 6

13

7

10

anonymous · Answer

okay but whats the proportion, i have no clue how to do this.

ganeshie8 · Answer

$\large \frac{AF}{FC} = \frac{AD}{DB}$

anonymous · Answer

i got 7..is that right?

ganeshie8 · Answer

$\large \frac{5}{6} = \frac{x+5}{18}$

ganeshie8 · Answer

7 looks incorrect. solve x above..

anonymous · Answer

5*18=90
so..6x+5=90
90-5=85
85/6= 14.16?

ganeshie8 · Answer

5*18=90
so..6(x+5)=90
6x+30 = 90
6x = 60

anonymous · Answer

but thats not one of the answers..

ganeshie8 · Answer

5*18=90
so..6(x+5)=90
6x+30 = 90
6x = 60
/6     /6

x = ?

anonymous · Answer

10!!!! :D

ganeshie8 · Answer

Yes ! :)

anonymous · Answer

THANK YOU SO MUCH

ganeshie8 · Answer

np :)