The slope of a line is -1/3, and the y-intercept is 10/3. What is the equation of the line written in general form?
10x + 3y - 1 = 0
x + 3y + 10 = 0
x + 3y - 10 = 0
i got as far as y=-1/3x+10/3
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OpenStudy (anonymous):
where do i go from there
OpenStudy (anonymous):
@texaschic101
OpenStudy (texaschic101):
y = -1/3x + 10/3
multiply the equation by 3 and tell me what you get
OpenStudy (texaschic101):
by doing this, it will get rid of the fractions
OpenStudy (anonymous):
kk brb
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OpenStudy (anonymous):
i got y=-1x+10
OpenStudy (texaschic101):
you have to multiply the y by 3 as well
OpenStudy (anonymous):
so 3=-1x+10 ?
OpenStudy (anonymous):
3y*
OpenStudy (texaschic101):
3y = -x + 10
now add x to both sides and subtract 10 from both sides and set it equal to zero
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OpenStudy (texaschic101):
we will do it in steps.....add x to both sides. This will cancel out the x's on the right side
OpenStudy (anonymous):
can you just show me how to do it im having trouble
OpenStudy (texaschic101):
3y = -x + 10 (add x to both sides)
3y + x = -x + x + 10
combine like terms
3y + x = 10
now subtract 10 from both sides
3y + x - 10 = 10 - 10
combine like terms
3y + x -10 = 0
x has to be first so change the equation around...
x + 3y - 10 = 0
OpenStudy (texaschic101):
understand ?
OpenStudy (anonymous):
yeh im writing all the steps down rite now
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