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how you would factor completely x^9 –27??
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do you know how to factor \(a^3-b^3\)?
are those cubed?
yes
would it be (x^3-3)(x^6+3x^3+9)
I really don't know how to do the difference of cubes
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\[a^3-b^3=(a-b)(a^2+ab+b^2)\]
rewrite your expression as the difference to two cubes and it should become clear what to do next
oh!! and 27 is actually 3^3!!!
bingo! well done! :)
thank you!!
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yw :)
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