Question

Evaluate: (17.2)/(25-4^-2)

Answer 1

Is this the question?

\( \dfrac{17.2} {25 - 4^{-2}} \)

Answer 2

yes

Answer 3

keep in mind that \(\bf \Large a^{-n} = \cfrac{1}{a^n}\)

Answer 4

\(\dfrac{17.2} {25 - 4^{-2}}\)

\(= \dfrac{17.2} {25 - \frac{1}{4^{2}} } \)

\(= \dfrac{17.2} {25 - \frac{1}{16} } \)

\(= \dfrac{17.2} {25 - 0.0625 } \)