Question

[8.01] Factor completely: −7x2 + 14x − 21

−1(x2 − 14x + 21)

−7x(x2 − 2x + 3)

−7(x2 + 2x − 3)

−7(x2 − 2x + 3)
I think its A help please

Answer 1

each term has a common factor of \(-7\)

Answer 2

yea

Answer 3

so not A

Answer 4

oh ok

Answer 5

gotta be
\[-7(\text{something})\]

Answer 6

ok

Answer 7

what would give you \(14x\) ? i .e. fill in the blank \(-7\times \)___ \(=14x\)

Answer 8

2

Answer 9

no actually \(-7\times2x=-14x\) but you want \(14x\)

Answer 10

ok

Answer 11

you need \(-2x\) because \(-7\times -2x=14x\)

Answer 12

ok

Answer 13

and finally you need \(-7\times \)____\(=-21\)

Answer 14

what would go in the blank?

Answer 15

3

Answer 16

yes \(+3\)

Answer 17

so \[−7x^2 + 14x − 21=-7(x^2-2x+3)\]

Answer 18

so its D

Answer 19

yes it is

Answer 20

nicely done :)