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What is the limit of (1-cos(h))^2 / h as h approaches zero?
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Do you know the limit \[\lim_{h\to0}\frac{1-\cos h}{h}~~~?\] You can rewrite your limit as \[\lim_{h\to0}\frac{(1-\cos h)^2}{h}=\lim_{h\to0}\frac{1-\cos h}{h}\cdot\lim_{h\to0}~(1-\cos h)\]
If you're not familiar with that first limit, you could evaluate it using the squeeze theorem.
Thanks. I completely forgot about rewriting the function.
You're welcome
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