I have another question A square piece of paper is folded in half. the perimeter of the resulting rectangle is 24cm. find the area of the original square paper. Please help

Question

I have another question A square piece of paper is folded in half.  the perimeter of the resulting rectangle is 24cm. find the area of the original square paper. Please help

anonymous · Answer

24+6=30..Original perimeter 30cm

anonymous · Answer

ow I got this answer x+x+x/2+x/2 = 3x 
3x=24
x=8 
The area of originalpaper is 8*8 = 64

anonymous · Answer

|dw:1376912465467:dw| In the drawing you will find the smaller square with sizes x and the 'folded out' larger rectangle with sizes 2x by x. 

For both I have incorporated the calculations of the Area (A) and the Circumference (C). Only one of these is given: the circumference of the square (C1), which is the same as the perimeter ofcourse.

You can solve C1 now because you know C1 = 24, which allows you to calculate x. Once found, you can calculate A2 by filling in x into the equation. Do you know how to do that ?

anonymous · Answer

ow