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Mathematics 11 Online
OpenStudy (anonymous):

A rental agent states that the average rent for a studio apartment in Shadyside is $750 A sample of 12 renters shows that the mean is $732 and the standard deviation is $17. Is there enough evidence to reject the agent's claim? Use a = .01

OpenStudy (amistre64):

use a 99% confidence interval ....

OpenStudy (amistre64):

\[732\pm Z_{99\%}(\frac{17}{\sqrt{12}})\] if 750 is within that range then you must fail to reject it

OpenStudy (amistre64):

or you can use the Pvalue stuff\[z=\frac{750-732}{17}\sqrt{12}\]

OpenStudy (amistre64):

3.67 seems to be beyond the limits to me at first glance; but thats just a guess at the moment .. whats the z score for 99.5% ?

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