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CALCULUS II: Determine where the tangent line is horizontal or vertical: x = 4 sin(2t) y = 2 cos(3t)
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y'=0 is horisontal x'=0 is vertical
y'=0 when sin 3t = 0 x' = 0 when cos 2t = 0
How would I find the points where one of these tangent lines occur?
solve for the zeros, then plug it into the xy parts that they gave you of course ...
I can do that..Thanks!
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spose x'=0 when t=k therefore: x = 4sin(2k) and y = 2cos(3k)
good luck :)
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