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Find the area of the shaded portion
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|dw:1376850359933:dw|
6 sin60=x/2 such that x is the length of the third side of triangle.. the area= Area of the big triangle -Area of the big arc +Area of the small triangle
|dw:1376929867224:dw| Remember, radii are perpendicular to tangents.
the last two are ready just since we know the lengths we want |dw:1376850781801:dw| so still just evaluate the first one
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the equation needs to be set up as so: A= \[?\sqrt{anumber}-anumber* \pi\]
okay that's what we will get just give a moment to find the area of the big one
|dw:1376929430496:dw|
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