Question

x varies inversely as y2, and x = 4 when y = 10. Find x when y = 2.

Answer 1

\[Let x=\frac{ k }{y ^{2} },or k=x *y ^{2}\]
plugging the values of x and y
\[k=4*10^{2}=400\]
Hence\[Hence x=\frac{ 400 }{ y ^{2}}\]
Now plug the value y=2 and find x.

Answer 2

x=200?

Answer 3

\[x=\frac{ 400 }{2^{2} }=\frac{ 400 }{4 }=100\]

Answer 4

Oh ok, I see now. Thanks

Answer 5

yw