Question

Find the limit as x approaches negative infinity of (6t^2 + 5t)/(1-t)(2t-3) Step by step would be great please!

Answer 1

Do you mean as \[t \rightarrow-\]?

Answer 2

yes

Answer 3

\[\lim_{t \rightarrow -\infty} \]
typing problem

Answer 4

\[\lim_{t \rightarrow -\infty}\frac{ 6t^2+5t }{ (1-t)(2t-3) }=\lim_{t \rightarrow -\infty}\frac{ 6t^2+5t }{ -2t^2+5t-3 }=\lim_{t \rightarrow -\infty}\frac{ 6t^2 }{ -2t^2 }=-3\]

The ratio of the coefficients of the leading terms determine the limits at infinity of a rational function when the degree of the numerator = degree of denominator.