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given an = 5n find a3
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hmm
if \[a_1 = 5*1\] and if \[a_2 = 5*2\] then \[a_3 = ???\]
an = 5n this could also be also said as a = 5 since its being multiplied and the n on each side can cancel out a=5 now a x 3 = ??? 5 x 3 = 15
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