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4t=48 ??? -x/3=27 ??? how do u solve these? alg 2
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Well fairly simple: \[t=\frac{ 48 }{ 4 } = 12\]
thanks could u help with 2nd question in same message please???
\[-x=27\times3\]\[-x=81\]\[x=-81\]
14.)15-g=23-2g ???? I really don't know how to solve???
\[15-g-15=23-2g-15\]\[-g = 8-2g\]\[-1g = 8 - 2g\] Same thing but I added a one so that you may understand. \[-1g + 2g = 8 - 2g +2g\]\[1g=8\] or \[g=8\]
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thanks soooo much(:
Hopefully you understood.
I did
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