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Mathematics 11 Online
OpenStudy (anonymous):

Express log[10] 0.01 = -2 using exponential notation

OpenStudy (anonymous):

\[\log_b(x)=y\iff b^y=x\]

OpenStudy (anonymous):

so \[\log_{10}(.01)=-2\iff ??\]

OpenStudy (anonymous):

10-2 = 0.01 ?

OpenStudy (anonymous):

yes assuming you mean \[10^{-2}=0.01\] which is a fact

OpenStudy (anonymous):

Yes, that's what I was saying. :)

OpenStudy (anonymous):

k good

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