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OpenStudy (anonymous):
How do I go about finding the slope of the curve at P(2, -3) and an equation of the tangent line at P for the function y = x^2-2x-3?
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OpenStudy (tkhunny):
You utilize your best algebra skills and you remember the Point-Slope form of a line. The point you are given. The slope comes from the 1st Derivative evaluated at x = 2. If it were me, I would first check to see that the point actually is on the given curve.
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