Question

PLEASE HELP :3
Samantha is going on vacation for the summer and is trying to choose between two different plans. The first plan costs $450 for 3 days at a hotel and 2 days at an amusement park. The second plan offers 5 days at the same hotel and 3 days at the amusement park for $700. The cost of 1 day at the hotel and the amusement park is the same under both plans. How much does a 1 day trip to the amusement park cost?

$50

$75

$150

$200

Answer 1

Solve 7x − 2y = −3
14x + y = 14

(4, 5/7)

(4, 7/5)

(5/7, 4)

(7/5, 4)

Answer 2

@mhmdrz91

Answer 3

Solve x + 3y = 9
3x − 3y = −13

(−1, 10/3)

(1, -10/3)

(−1, 3/10)

(1, -3/10)

Answer 4

7x - 2y = -3 => 7x = 2y-3
14x + y = 14 => 7x +y/2 = 7 => 7x = 7-y/2
now 2y-3 = 7-y/2
2y+y/2 = 10 -> 5y/2 = 10 -> 5y = 20 -> y = 4

7x-8=-3 -> 7x = 5 -> x = 5/7

answer is (5/7,4)

Answer 5

for x+3y=9 and 3x - 3y = -13 use same as last solution ;-)

Answer 6

Huh?

Answer 7

What do u mean last solution?

Answer 8

7x - 2y = -3
14x + y = 14

solution for this :D

Answer 9

Oh.. im confused.. I do the same thing for the last one that u did for the 7x one?

Answer 10

x + 3y = 9 => 3x = 27 - 9y
3x − 3y = −13 => 3x = 3y -13
27-9y = 3y -13 -> 12y = 40 -> y = 40/12 = 10/3

x + 3*(10/3) = 9 -> x = 9 - 10 = -1

(-1 , 10/3) is answer