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how do you get the value of csc (5pi/4) with the unit circle
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First, it helps to know this: \( \csc x= \dfrac{1}{\sin x} \)
you use a "good" unit circle, a good one will have it there :)
oh, ohh csc, well csc = 1/sin as mathstudent55 said, so your "good" unit circle will have the sine functions too :)
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