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Without using a calculator, find the exact value of cos^-1(cos(17pi/5)). Thanks for the help :)
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what's your knowing about \[Cos(x)\]and\[Cos^{-1} (x)\]
simplify arccos(cos(17pi/5))
which reduces to arccos(cos(7pi/5))
arcsin(sin(x)) = x and arccos(cos(x)) = x
^^^ is true, IF x is in the range of the inverse function. If not, you need the angle that has the same function value AND is in the range. (Just a little caveat.)
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Same question was asked yesterday: http://openstudy.com/study#/updates/52129ad4e4b0450ed75d8324 and note that 7pi/5 is NOT in the range of y=arccos(x)
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