Question

two ships leave a port at 9am. one travels at a bearing of N 53 degrees W at 12 miles per hour, and the other travels at a bearing of S 67 degrees W at 16 miles per hour. Approximately how far apart there are at noon that day.

Answer 1

step 1 is find sides of the triangle
12 m/h and 16 m/h for how three hrs

a = ?
b=?

what is the angle between them??
remember we have the vertical axis at 180
so 180 - 53-67=??

the use the law of cosine
c(or side we want)
c^2 = a^2xb^2-2abcos( of angle between)