Question

Solve for x
X^2-4x+3x-2=28

Answer 1

You can also write this as
x^2 -x -2 - 28 = 0 right?
So
x^2 - x - 30 = 0
Now split the middle term!
The terms used in splitting should multiply to 30 but add/subtract to the co-eff of x.
We have 6 and 5 that multiply to 30 and when subtracted give us 1!!! :D
So we write this as
x2 - 6x + 5x - 30 = 0
x(x-6) + 5(x-6) = 0
Or
(x+5)(x-6) = 0
Understood? :D

Answer 2

Now x would be?
-5 and 6
Getting me? :D

Answer 3

Well yes and no. The original question was: Point K is between J and L. If JK = x^2-4x, KL=3x -2 and JL=28, write and solve an equation to find the lengths of JK and KL. The one you solved was my "equation"