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A coin is tossed 5 times but you get 6 heads? Not sure how on that one :P
\[\Large {P(n)=\left\{\matrix {C(N,n)\left(\frac{1}{2}\right)^n\left(\frac{1}{2}\right)^{N-n} & n=0,1,2,\dots,N\\0 & \text{otherwise} }\right.}\]
with \[N=5,n=6\] \[P(6)=0\]
it means i have done wrong
yes. the probability density function should be stated as P(x) = formula for possible cases of x, and P(x) = 0 otherwise.
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whats answer
plse guide me
@sirm3d
The answer is 0. There is no way to get 6 heads in 5 tosses. That's what everyone was trying to hint at.
The way the question is set up I would say there is a mistake. Maybe N=50?
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Or maybe 5 heads out of 6 tosses.
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