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keep in mind that => \(\Huge a^{-n} = \cfrac{1}{a^n}\)
also keep in mind that \(\Huge a^{\frac{n}{m}} = \sqrt[m]{a^n}\)
\(\bf \Large (\square^{-m})^{-\frac{a}{b}} \implies \sqrt[b]{(\square^{-m})^a} \implies \sqrt[b]{\left(\cfrac{1}{\square^{m}}\right)^a}\)
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