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\(\bf b^n \times b^m = \square? \ \ ?\)
you need to organize the square root as follows: b^16, since the root is cubed, then you have (b^3, b^3, b^3, b^3,b^3,b^3,b) if you add the exponents you have (3+3+3+3+3+1 = 16) which is what you have b^16
so how many b^3 do you have ??
oops, it is (b^3,b^3,b^3,b^3,B^3,b)
cube root of b^16 = cube root of b^15*b removing the 15 from the cube root turns it into 5 Does that help you?
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