Question

Identify the range of the equation y = −x2 − 8x − 10.

All real numbers

y ≥ −2

y ≤ 6

y ≤ −4

Answer 1

\[x ^{2}+8x+10+y=0\]
\[for x be real D \ge 0, 8^{2}-4\left( 10+y \right) \ge 0\]
\[64-40-4y \ge 0,24-4y \ge 0,-4y \ge -24, y \le 6\]
\[Range is y \le 6\]