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Find the sum of each arithmetic series. the first 100 odd natural numbers.
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@amistre64 @zzr0ck3r @radar
\[\sum_{n=1}^{100}2n-1=\sum_{n=1}^{100}2n-\sum_{n=1}^{100}1=2\sum_{n=1}^{100}n-\sum_{n=1}^{100}1\]
\[2\frac{100*101}{2}-100\]
100*100 = 10000
I stole @amistre64 method:)
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1+3+5+....+99 199+197+.....101 add them top to bottom 200*50 = 10000
Thanks
np
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