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Mathematics 19 Online
OpenStudy (anonymous):

How do I solve this? 2003*1999-1997*1993

OpenStudy (anonymous):

@Directrix @jim_thompson5910

OpenStudy (loser66):

just 2 terms? no x? no series? just calculate?

OpenStudy (anonymous):

yea, it says to evaluate

OpenStudy (anonymous):

i was thinking of this (2001+2)(2001-2)-(1995+2)(1995-2), but I don't know what to do now?

jimthompson5910 (jim_thompson5910):

use the difference of squares rule to get 2001^2 - 2^2 - (1995^2 - 2^2)

OpenStudy (anonymous):

then what?

jimthompson5910 (jim_thompson5910):

distribute that negative through

OpenStudy (anonymous):

but how would i solve for 2001^2

jimthompson5910 (jim_thompson5910):

what do you have so far

OpenStudy (anonymous):

2001^2-2^2-1995^2+2^2

OpenStudy (anonymous):

nevermind i got it

jimthompson5910 (jim_thompson5910):

ok great

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