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How do I solve this? 2003*1999-1997*1993
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@Directrix @jim_thompson5910
just 2 terms? no x? no series? just calculate?
yea, it says to evaluate
i was thinking of this (2001+2)(2001-2)-(1995+2)(1995-2), but I don't know what to do now?
use the difference of squares rule to get 2001^2 - 2^2 - (1995^2 - 2^2)
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then what?
distribute that negative through
but how would i solve for 2001^2
what do you have so far
2001^2-2^2-1995^2+2^2
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nevermind i got it
ok great
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