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Mathematics 7 Online
OpenStudy (anonymous):

(_____)^(2) = (csc x-1)(csc x+1)

OpenStudy (debbieg):

Did you take the product on the right hand side?

OpenStudy (debbieg):

And do you know the Pythagorean identities?

OpenStudy (anonymous):

So I have :\[\csc^2x - 1 = (cotx)^2\]

OpenStudy (anonymous):

Is this correct?

OpenStudy (loser66):

yup

OpenStudy (debbieg):

Yes indeedy. :)

OpenStudy (anonymous):

:3

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