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OpenStudy (anonymous):
Trig Identities : check 5sin(2x) = 3cosx
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OpenStudy (anonymous):
I had to rewrite it. So I got 5(2sinx cosx) = 3cosx
OpenStudy (anonymous):
the I distributed to get 10sinx cosx - 3 cosx = 0
OpenStudy (anonymous):
so would the final be cosx (10sin x - 3) ?
OpenStudy (anonymous):
choices were: cosx(5sinx-3)=0 5sinx+3cosx=0 cosx(10sinx-3)=0
OpenStudy (anonymous):
I think it's the last one, because I would do the same thing you did
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OpenStudy (anonymous):
Yeah. Me too.
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