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\[\frac{ 4x-20 }{ 4x }\]
you can convert the 4x-20 as 4(x-5) ------ 4x
now you can cancel the 4 and you have x-5 ----- x
Thanks! what about\[\frac{ x ^{2} -16}{ x ^{2}-8x+16 }\]
?
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Do you understand how we are solving these?
Kindof
that is right
what don't you understand on how to solve the type of questions you have? do you understand on how to factor out the question? because the way it was solved is by little bird was right.
factor top factor bottom cancel common factors
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to find the factors ax ^{2}+bx+c find a*c If ac >0 ,then break b in p,q such that b=p+q and p*q=a*c if ac<0,then b=p-q such that p*q=a*c
Thanks to everyone thats helped. :-)
yw
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