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Write line equation that is perpendicular to the given line and that passes through the given point. 4x-12y=2; (10,-1)
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what's the slope of 4x-12y=2?
How would I go about figuring that?
solve for "y"
1/3?
yes, 1/3 sorry I was a bit away a line perpendicular to that will have a NEGATIVE RECIPROCAL slope to that what does that mean? RECIPROCAL OF 1/3 3/1 NEGATIVE OF THAT -3 then using the point-slope form \(\bf y-y_1=m(x-x_1)\) plug those values in m = slope = -3 \(\bf (x_1, y_1) = (10, -1)\)
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