Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 4x − ___

Answer 1

x intercepts at x = -6 and x = 2.

so get the roots from there and expand

\(\bf x = -6 \implies x+6=0 \qquad \textit{root }(x+6)\\
x = 2 \implies x-2 = 0 \qquad \textit{root }(x-2)\\
(x+6)(x-2) = x^2+4x + \square?\)

Answer 2

I have no clue

Answer 3

what is \(2\times 6\) ?

Answer 4

12

Answer 5

thats it?