HELP PLEASE!

The figure below shows CB = 4, BE = 5, AB = x - 4, and DB = x + 3.

Triangle ABC is a right triangle with measure of angle ACB equal to 90 degrees. The measure of side CB is 4 and AB is x minus four. D is a point on the left of C on BC extended. A point E is labeled on AB such that DE is perpendicular to AB. Measure of EB is 5 and DB is x plus 3.

If △ABC ~ △DBE, the value of x is _________

Question

HELP PLEASE! 

The figure below shows CB = 4, BE = 5, AB = x - 4, and DB = x + 3. 

Triangle ABC is a right triangle with measure of angle ACB equal to 90 degrees. The measure of side CB is 4 and AB is x minus four. D is a point on the left of C on BC extended. A point E is labeled on AB such that DE is perpendicular to AB. Measure of EB is 5 and DB is x plus 3.

If △ABC ~ △DBE, the value of x is _________

anonymous · Answer

attachment

anonymous · Answer

I don't understand this ):

anonymous · Answer

you are given 2 triangles that are similar. therefore the corresponding parts are proportional.

anonymous · Answer

You can set up a ratio and proportion

anonymous · Answer

How do I do that?

anonymous · Answer

EB/CB = DB/AB
Plug in the given values, and you can now solve for x

anonymous · Answer

Gah, I don't know ): Can't figure it out!

anonymous · Answer

5/4 = (X+3)/ (X-4)
You can now cross multiply
5(x-4) = 4(x + 3)
I guess you can do the rest

anonymous · Answer

don't forget the distributive property

anonymous · Answer

-8 or 8?

anonymous · Answer

5X -20 = 4X + 12
You can now solve for x

anonymous · Answer

42?

anonymous · Answer

20+ 12 = ?

anonymous · Answer

32 lol

anonymous · Answer

Hahaha! you are careless. Just be more confident. Students tend to be confused when they are tense