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OpenStudy (anonymous):
help anyone??? What is the equation of the line of symmetry for the graph of y = –2(x – 4)2 + 3?
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OpenStudy (anonymous):
\[y=-2(x-4)^2+3\] right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
this is written in vertex form \[y=a(x-h)^2+k\] the axis of symmetry is \(x=h\)
OpenStudy (anonymous):
oh wow that is so simple thank you!
OpenStudy (anonymous):
yw
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OpenStudy (anonymous):
and yes, it is simple
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