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(8x^6y^-3)^1/3 how do you do this?
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It is the same as this: \[\sqrt[3]\frac{8x^6}{y^3}\]
how do you solve this tho? it's going to be like 2x^3/?
multply each exponent by \(\frac{1}{3}\)
so is this going to be like \[2x^2/y^-1?\]
\[\frac{2x^2}{y}\]
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