Ask your own question, for FREE!
Mathematics 26 Online
OpenStudy (anonymous):

a(y+c)=b(y-c) solve for y

OpenStudy (abb0t):

@nincompoop

OpenStudy (nincompoop):

a(y+c) = b(y-c) *use distributive property* ay + ac = by - bc *put terms with y together* ay + ac - ac - by = by - by - bc - ac *perform the operation* ay - by = -ac - bc *factor* y(a-b) = c(-a-b) *solve for y by dividing both sides by (a-b)* y = [c(-a-b)]/(a-b)

OpenStudy (nincompoop):

something's amiss … whatever LOL

OpenStudy (nincompoop):

OpenStudy (bahrom7893):

a(y+c)=b(y-c) ay + ac = by - bc ay - by = - ac - bc y(a-b) = -c(a+b) y = -c(a+b)/(a-b)

OpenStudy (bahrom7893):

nin was right.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!